Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
456 views
in Technique[技术] by (71.8m points)

c++ - How to implement a QThread that runs forever{} with a QWaitCondition but still needs to catch another Slot while doing that

I implemented a class that can write data to a serial port via a QQueue and read from it by a slot. I use QAsyncSerial for this which in turn uses boost::asio with a callback. The class is moved to a thread and its start() method is executed when the QThread emits "started()"

The problem is that I dequeue the QQueue in the start()-method using forever {} and a QWaitCondition. While this is running (which obviously runs forever) the slot connected to the dataReceived signal of QAsyncSerial can not be called, thus I never read anything from the serial port.

What is the usual approach to this problem?

SerialPortHandler::SerialPortHandler(SerialPort serialPort, QObject *parent) : QObject(parent), serialPort(serialPort)
{
    m_enqueueMessageMutex = new QMutex();
    m_messageQueue = new QQueue<BaseMessage*>();
    m_waitCondition = new QWaitCondition();
    serial.open(serialPort.deviceName(), 2400);
    connect(&serial, SIGNAL(dataReceived(QByteArray)), this, SLOT(serialSlotReceivedData(QByteArray)));
}

void SerialPortHandler::serialSlotReceivedData(QByteArray line)
{
    qDebug() << QString(line).toAscii();
}

void SerialPortHandler::sendTestPing()
{
    PingMessage *msg = new PingMessage();
    enqueueMessage(msg);
}

void SerialPortHandler::enqueueMessage(BaseMessage *msg)
{
    QMutexLocker locker(m_enqueueMessageMutex);
    m_messageQueue->enqueue(msg);
    m_waitCondition->wakeAll();
}

void SerialPortHandler::start()
{
    if (!serial.isOpen())
        return;

    forever {
        m_enqueueMessageMutex->lock();
        if (m_messageQueue->isEmpty())
            m_waitCondition->wait(m_enqueueMessageMutex);
        BaseMessage *msg = m_messageQueue->dequeue();
        serial.write(msg->encodeForWriting());
        m_enqueueMessageMutex->unlock();
    }
}

The changed QAsyncSerial callback used by boost::asio:

void QAsyncSerial::readCallback(const char *data, size_t size)
{
    emit dataReceived(QByteArray::fromRawData(data, (int) size));
}

Edit:

I solved this problem with another approach. I ditched QAsyncSerial and instead used the CallbackAsyncSerial which is also distributed by QAsyncSerial directly. Now the callback used by boost::asio is the serialSlotReceivedData "slot". This "solves" the problem since the callback is called in the thread boost::asio runs in. Since it has its own thread it doesn't matter that the thread SerialPortHandler runs in is blocked by the forever loop.

New code: (since QAsyncSerial is something like a wrapper to CallbackAsyncSerial only some trivial things changed)

SerialPortHandler::SerialPortHandler(SerialPort serialPort, QObject *parent) : QObject(parent), serialPort(serialPort)
{
    m_enqueueMessageMutex = new QMutex();
    m_messageQueue = new QQueue<BaseMessage*>();
    m_waitCondition = new QWaitCondition();
    /* serial is now CallbackAsyncSerial and not QAsyncSerial */
    serial.open(QString(serialPort.deviceName()).toStdString(), 2400);
    serial.setCallback(bind(&SerialPortHandler::serialSlotReceivedData, this, _1, _2));

    m_messageProcessingState = MessageProcessingState::Inactive;
}

void SerialPortHandler::start()
{
    if (!serial.isOpen())
        return;

    forever {
        m_enqueueMessageMutex->lock();

        if (m_messageQueue->isEmpty())
            m_waitCondition->wait(m_enqueueMessageMutex);

        BaseMessage *msg = m_messageQueue->dequeue();
        QByteArray encodedMessage = msg->encodeForWriting();
        serial.write(encodedMessage.constData(), encodedMessage.length());

        m_enqueueMessageMutex->unlock();
    }
}
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

1) Create slot in your thread, for example onMessageReady(), which will do the job.

2) Create a signal indicates that new message ready, and emit it each time you creating a new message.

3) Connect them using QueuedConnection and call your thread's exec function.

This won't block your thread, as WaitforObject does, and you will handle all incoming signals.

something like this:

SerialPortHandler: public QThread
{
  Q_OBJECT
...
signals:
    void sNewMessageReady();
slots:
    void onNewMessageReady();
    void serialSlotReceivedData(QByteArray);
};

SerialPortHandler::SerialPortHandler(SerialPort serialPort, QObject *parent) : QThread(parent), serialPort(serialPort)
{
    m_enqueueMessageMutex = new QMutex();
    m_messageQueue = new QQueue<BaseMessage*>();
    serial.open(serialPort.deviceName(), 2400);
    connect(&serial, SIGNAL(dataReceived(QByteArray)), this, SLOT(serialSlotReceivedData(QByteArray)));
    connect(this, SIGNAL(sNewMessageReady()), this, SLOT(onNewMessageReady()),Qt::QueuedConnection);
}

void SerialPortHandler::enqueueMessage(BaseMessage *msg)
{
    QMutexLocker locker(m_enqueueMessageMutex);
    m_messageQueue->enqueue(msg);
    emit sNewMessageReady();
}


void SerialPortHandler::onNewMessageReady()
{
    QMutexLocker locker(m_enqueueMessageMutex);
    BaseMessage *msg = m_messageQueue->dequeue();
    serial.write(msg->encodeForWriting());
}

after all simply call thread's exec() method, you don't need to reimplement run() and to use QWaitCondotion at all.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...