To do this accurately, you should use event detection within the ODE solver. I can't give you a specific answer because you've only provided the ode15s
call it in your question, but you'll need to write an events
function and then specify it via odeset
. Something like this:
function acidity_main
% load c data
...
x0 = ...
options = odeset('Events',@events); % add any other options too
% integrate until critical value and stop
[Time1,Results1] = ode15s(@(x,c)f1(x,c),[0 c.length],x0,options);
x0 = Results(end,:); % set new initial conditions
% pass new parameters -it's not clear how you're passing parameters
% if desired, change options to turn off events for faster integration
[Time2,Results2] = ode15s(@(x,c)f1(x,c),[0 c.length],x0,options);
% append outputs, last of 1 is same as first of 2
Time = [Time1;Time2(2:end)];
Results = [Results1;Results2(2:end,:)];
...
function y=f1(x,c)
% your integration function
...
function [value,isterminal,direction] = events(x,c)
value = ... % crossing condition, evaluates to zero at event condition
isterminal = 1; % stop integration when event detected
direction = ... % see documentation
You'll want to use the events to integrate right to the point where the "acidicity reaches a critical point" and stop the integration. Then call ode15s
again with the new value and continue the integration. This may seem crude, but it how this sort of thing can be done accurately.
You can see an example of basic event detection here. Type ballode
in your command window to see the code for this. You can see a slightly more complex version of this demo in my answer here. Here's an example of using events to accurately change an ODE at specified times (rather than your case of specified state values).
Note: I find it strange that you're passing what you call "constants", c
, as the second argument to ode15s
. This function has strict input argument requirements: the first is the independent variable (often time), and the second is the array of state variables (same as your initial condition vector). Also if f1
only takes two arguments, @(x,c)f1(x,c)
is superfluous – it's sufficient to pass in @f1
.
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