Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
581 views
in Technique[技术] by (71.8m points)

perl - How do I average column values from a tab-separated data file, ignoring a header row and the left column?

My task is to compute averages from the following data file, titled Lab1_table.txt:

retrovirus      genome  gag     pol     env
HIV-1           9181    1503    3006    2571
FIV             9474    1353    2993    2571
KoRV            8431    1566    3384    1980
GaLV            8088    1563    3498    2058
PERV            8072    1560    3621    1532

I have to write a script that will open and read this file, read each line by splitting the contents into an array and computer the average of the numerical values (genome, gag, pol, env), and write to a new file the average from each of the aforementioned columns.

I've been trying my best to figure out how to not take into account the first row, or the first column, but every time I try to execute on the command line I keep coming up with 'explicit package name' errors.

Global symbol @average requires explicit package name at line 23.
Global symbol @average requires explicit package name at line 29.
Execution aborted due to compilation errors.

I understand that this involves @ and $, but even knowing that I've not been able to change the errors.

This is my code, but I emphasise that I'm a beginner having started this just last week:

#!/usr/bin/perl -w
use strict;

my $infile = "Lab1_table.txt"; # This is the file path
open INFILE, $infile or die "Can't open $infile: $!";

my $count = 0;
my $average = ();

while (<INFILE>) {
    chomp;
    my @columns = split //;
    $count++;
    if ( $count == 1 ) {
        $average = @columns;
    }
    else {
        for( my $i = 1; $i < scalar $average; $i++ )  {
            $average[$i] += $columns[$i];
        }
    }
}

for( my $i = 1; $i < scalar $average; $i++ ) {
    print $average[$i]/$count, "
";
}

I'd appreciate any insight, and I would also great appreciate letting me know by list numbering what you're doing at each step - if appropriate. I'd like to learn and it would make more sense to me if I was able to read through what someone's process was.

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Here are the points you need to change
Use another variable for the headers

my $count = 0;
my @header = ();
my @average = ();

then change the logic inside if statement

if ( $count == 1 ) {
    @header = @columns;
}

Now don't use the @average for the limit, use $i < scalar @columns for else statement. Initially @average is zero, you will never get inside the for loop ever.

else {
    for( my $i = 1; $i < scalar @columns; $i++ )  {
        $average[$i] += $columns[$i];
    }
}

Finally add -1 to your counter. Remember you increment your counter when you parse your header

for( my $i = 1; $i < scalar @average; $i++ ) {
    print $average[$i]/($count-1), "
";
}

Here is the final code
You can take advantage of @header to display the result neatly

#!/usr/bin/perl -w

use strict;

my $infile = "Lab1_table.txt"; # This is the file path
open INFILE, $infile or die "Can't open $infile: $!"; 

my $count = 0;
my @header = ();
my @average = ();

while (<INFILE>) {
    chomp;


    my @columns = split //;
    $count++;
    if ( $count == 1 ) {
        @header = @columns;
    }
    else {
        for( my $i = 1; $i < scalar @columns; $i++ )  {
            $average[$i] += $columns[$i];
        }
    }
} 

for( my $i = 1; $i < scalar @average; $i++ ) {
    print $average[$i]/($count-1), "
";
}

There are other ways to write this code but I thought it would be better to just correct your code so that you can easily understand what is wrong with your code. Hope it helps


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...