c - problem with printf function?

Question

i wrote the following program

 #include <stdio.h>

 main()
 {
 int i = 2;
 float c = 4.5;
 printf("%d
",c);
 printf("%f
",i);
 return 0;
 }

though i know this is the wrong practice,when i run the program i got the answer as

0
4.500000

but when i exchanged the printf statements a little bit this way

#include <stdio.h>

main()
{
int i = 2;
float c = 4.5;
printf("%f
",i);
printf("%d
",c);
return 0;
}

the output was

0.000000
0

i couldn't understand whats happening ,any one pls explain me.

Answer 1

printf doesn't convert it's arguments. It's looking at the memory containing a float and printing it as if it were an integer - it's like taking an MP3 file and asking word to open it as if it were a doc.

A floating point number is stored in a completely different way in memory to an integer - it's not just an integer with some decimal points