Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
542 views
in Technique[技术] by (71.8m points)

c++ - Optimizing a floating point division and conversion operation

I have the following formula

float mean = (r+b+g)/3/255.0f;

I want to speed it up. There are the following preconditions

0<= mean <= 1  and 0 <= r,g,b <= 255 and r, g, b are unsigned chars

so if I try to use the fact that >> 8 is like dividing by 256 and I use something like

float mean = (float)(((r+b+g)/3) >> 8);

this will always return 0. Is there a way to skip the costly float division and still end up with a mean between 0 and 1?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

Pre-convert your divisions into a multiplicable constant:

a / 3 / 255

is the same as

a * (1 / (3 * 255))

so pre-compute:

const float AVERAGE_SCALE_FACTOR = 1.f / (3.f * 255.f)

then just do

float mean = (r + g + b) * AVERAGE_SCALE_FACTOR;

since multiplying is generally a lot faster than dividing.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...