I am trying to call a function within a function using sql on postgres 9.3.
This question is related to another post by me.
I have written the below function. So far I have failed to incorporate any kind of save-output (COPY) statement, so I am trying to work around this by creating a nested function print-out function.
CREATE FUNCTION retrieve_info(TEXT, TEXT) RETURNS SETOF
retrieve_info_tbl AS $$
SELECT tblA.id, tblA.method, tblA.species, tblA.location
FROM tblA
WHERE method=$1 AND species=$2
GROUP BY id, method, species
ORDER BY location
$$ LANGUAGE 'sql';
The above function works.
An attempt to create a nested function.
CREATE FUNCTION print_out(TEXT, TEXT) RETURNS void AS $$
COPY (SELECT * FROM retrieve_info($1, $2)) TO 'myfilepath/test.csv'
WITH CSV HEADER;
$$ LANGUAGE 'sql';
Calling nested function.
SELECT * FROM print_out('mtd1','sp1');
OUTPUT
The above gives this ERROR: column "$1" does not exist SQL state: 42P02 Context: SQL function "print_out" statement 1
. However, when substituting the arg1, arg2 in print_out() with 'mtd1','sp1' the correct output is printed to test.csv (as seen below)
id | method | ind | location
----------------------------
1a | mtd1 | sp3 | locA
1d | mtd1 | sp3 | locB
How would I get the arg1, arg2 of retrieve_info() to call arg1, arg2 properly within print_out()?
I am completely stuck. Would appreciate any pointers, thanks
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