Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
598 views
in Technique[技术] by (71.8m points)

ios - Catch "IndexOutOfBoundsException" in Swift 2

I got this code in my Playground:

func throwsError() throws{
    var x = [1,2]
    print(x[3])
}

func start(){

    do{
        try throwsError()

    }
    catch let unknown{
        "unknown: (unknown)"
    }
}

start()

So obviously the'throwsError function throws an error:

Execution was interrupted, reason: EXC_BAD_INSTRUCTION

Is there a way to catch this? I read online to write a subscript for the Array class that always checks for range but the issue is bigger: Am I not capable to just catch anything?

See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

In Swift, you can't catch anything. You can only catch errors thrown with the throw statement in other Swift code or errors, of type NSError set by called Objective C code.

The default array subscript raises an exception, but does not throw a Swift error, so you cannot use try/catch with it.

See also this article by Erica Sadun.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...