I know that I can perform divide by 2 using right shift.
For simplicity, take a 4 bit number system
-1 - 1111
-2 - 1110
-3 - 1101
-4 - 1100
-5 - 1011
-6 - 1010
-7 - 1001
-8 - 1000
7 - 0111
6 - 0110
5 - 0101
4 - 0100
3 - 0011
2 - 0010
1 - 0001
0 - 0000
If I try to perform
6 / 2 = 0110 >> 1 = 0011 = 3
-6/ 2 = 1010 >> 1 = 1101 = -3
Is valid for both +ve and -ve number
However, when come to 1
1 / 2 = 0001 >> 1 = 0000 = 0
-1/ 2 = 1111 >> 1 = 1111 = -1
Seems like there is a special case in -1, as right shift then to move it to negative infinity.
Currently, I need to put a special if check for this, as I am expecting -1 / 2 = 0.
I was wondering how do you guy handle this exception in your code? You guy put an if check?
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