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c - Is the strict aliasing rule really a "two-way street"?

In these comments user @Deduplicator insists that the strict aliasing rule permits access through an incompatible type if either of the aliased or the aliasing pointer is a pointer-to-character type (qualified or unqualified, signed or unsigned char *). So, his assertion is basically that both

long long foo;
char *p = (char *)&foo;
*p; // just in order to dereference 'p'

and

char foo[sizeof(long long)];
long long *p = (long long *)&foo[0];
*p; // just in order to dereference 'p'

are conforming and have defined behavior.

In my read, however, it is only the first form that is valid, that is, when the aliasing pointer is a pointer-to-char; however, one can't do that in the other direction, i. e. when the aliasing pointer points to an incompatible type (other than a character type), the aliased pointer being a char *.

So, the second snippet above would have undefined behavior.

What's the case? Is this correct? For the record, I have already read this question and answer, and there the accepted answer explicitly states that

The rules allow an exception for char *. It's always assumed that char * aliases other types. However this won't work the other way, there's no assumption that your struct aliases a buffer of chars.

(emphasis mine)

See Question&Answers more detail:os

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You are correct to say that this is not valid. As you yourself have quoted (so I shall not re-quote here) the guaranteed valid cast is only from any other type to char*.

The other form is indeed against standard and causes undefined behaviour. However as a little bonus let us discuss a little behind this standard.

Chars, on every significant architecture is the only type that allows completely unaligned access, this is due to the read byte instructions having to work on any byte, otherwise they would be all but useless. This means that an indirect read to a char will always be valid on every CPU I know of.

However the other way around this will not apply, you cannot read a uint64_t unless the pointer is aligned to 8 bytes on most arches.

However, there is a very common compiler extension allowing you to cast properly aligned pointers from char to other types and access them, however this is non-standard. Also note, if you cast a pointer to any type to a pointer to char and then cast it back the resultant pointer is guaranteed to be equal to the original object. Therefore this is ok:

struct x *mystruct = MakeAMyStruct();
char * foo = (char *)mystruct;
struct x *mystruct2 = (struct mystruct *)foo;

And mystruct2 will equal mystruct. This also guarantees the struct is properly aligned for it's needs.

So basically, if you want a pointer to char and a pointer to another type, always declare the pointer to the other type then cast to char. Or even better use a union, that is what they are basically for...

Note, there is a notable exception to the rule however. Some old implementations of malloc used to return a char*. This pointer is always guaranteed to be castable to any type successfully without breaking aliasing rules.


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