c - how to replace a char in char *

Question

total newbie here. i was trying to replace a character in char * but my program gives error

#include <stdio.h>

int main(int argc, char **argv)
{
    char *mystring ="love is alweys better yoe";
    int count = 1;

    for (count ;  count < 23; count++)
    {     
    if ((mystring[count] == 0x65 )) //&& ((mystring[count+1] > 0x41) && (mystring[count+1] < 0x7A))) 
    {
      mystring[count] = 0x45; //here occur the freezing
      printf ("%c
", mystring[count]); 
      //break;
    };
    };

    printf("%s
",mystring);
    return 0;
}

Answer 1

The

char *mystring ="love is alweys better yoe"

makes mystring read-only

you need to copy the string into a buffer before you can change it

e.g.

char mystring[128];
strcpy( mystring , "love is alweys better yoe" );