Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Welcome To Ask or Share your Answers For Others

Categories

0 votes
332 views
in Technique[技术] by (71.8m points)

telnet - Python telnetlib: surprising problem

I am using the Python module telnetlib to create a telnet session (with a chess server), and I'm having an issue I really can't wrap my brain around. The following code works perfectly:

>>> f = login("my_server") #code for login(host) below.
>>> f.read_very_eager()

This spits out everything the server usually prints upon login. However, when I put it inside a function and then call it thus:

>>> def foo():
...   f = login("my_server")
...   return f.read_very_eager()
...
>>> foo()

I get nothing (the empty string). I can check that the login is performed properly, but for some reason I can't see the text. So where does it get swallowed?

Many thanks.

For completeness, here is login(host):

def login(host, handle="guest", password=""):
try:
    f = telnetlib.Telnet(host) #connect to host
except:
    raise Error("Could not connect to host")
f.read_until("login: ")
try:
    f.write(handle + "

")
except:
    raise Error("Could not write username to host")
if handle == "guest":
    f.read_until(":

")
else:
    f.read_until("password: ")
try:
    f.write(password + "

")
except:
    raise Error("Could not write password to host")
return f
See Question&Answers more detail:os

与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome To Ask or Share your Answers For Others

1 Answer

0 votes
by (71.8m points)

The reason why this works when you try it out manually but not when in a function is because when you try it out manually, the server has enough time to react upon the login and send data back. When it's all in one function, you send the password to the server and never wait long enough for the server to reply.

If you prefer a (probably more correct) technical answer:

In file telnetlib.py (c:python26Libelnetlib.py on my Windows computer), function read_very_eager(self) calls self.sock_avail() Now, function sock_avail(self) does the following:

def sock_avail(self):
    """Test whether data is available on the socket."""
    return select.select([self], [], [], 0) == ([self], [], [])

What this does is really simple: if there is -anything- to read from our socket (the server has answered), it'll return True, otherwise it'll return False.

So, what read_very_eager(self) does is: check if there is anything available to read. If there is, then read from the socket, otherwise just return an empty string.

If you look at the code of read_some(self) you'll see that it doesn't check if there is any data available to read. It'll try reading till there is something available, which means that if the server takes for instance 100ms before answering you, it'll wait 100ms before returning the answer.


与恶龙缠斗过久,自身亦成为恶龙;凝视深渊过久,深渊将回以凝视…
Welcome to OStack Knowledge Sharing Community for programmer and developer-Open, Learning and Share
Click Here to Ask a Question

...