I've been trying for awhile to combine mutate_at
with coalesce
in case in which names of columns are generated dynamically.
In my example there are only five columns, but in the real data there are much more (and not all columns should be included in coalesce
step).
Example DF:
data_example <- data.frame(
aa = c(1, NA, NA),
bb = c(NA, NA, 2),
cc = c(6, 7, 8),
aa_extra = c(2, 2, NA),
bb_extra = c(1, 2, 3)
)
Expected output:
aa bb cc aa_extra bb_extra
1 1 1 6 2 1
2 2 2 7 2 2
3 NA 2 8 NA 3
output as structure
:
structure(list(aa = c(1, 2, NA), bb = c(1, 2, 2), cc = c(6, 7,
8), aa_extra = c(2, 2, NA), bb_extra = c(1, 2, 3)), class = "data.frame", row.names = c(NA,
-3L))
I've tried something like this, but without success ("Only strings can be converted to symbols"). I would like to avoid creation of extra variables, just include everything in mutate_at
expression, since this is a part of longer dplyr "flow".
data_example %>%
dplyr::mutate_at(
gsub("_extra", "", grep("_extra$",
colnames(.),
perl = T,
value = T)),
dplyr::funs(
dplyr::coalesce(., !!! dplyr::sym(paste0(., "_extra")))
)
)
I've tried also this (no error, but values for column bb
are wrong):
data_example %>%
dplyr::mutate_at(
gsub("_extra", "", grep("_extra$",
colnames(.),
perl = T,
value = T)),
dplyr::funs(
dplyr::coalesce(., !!as.name(paste0(names(.), "_extra")))
)
)
How to get the name of processed column and pass it to coalesce
?
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