I had a similar issue and found a very workable pattern that works well with argparse (here three key-pairs: foo, bar and baz:
mycommand par1 --set foo=hello bar="hello world" baz=5
1. Defining the optional, multivalued argument
The set argument must be defined so:
import argparse
parser = argparse.ArgumentParser(description="...")
...
parser.add_argument("--set",
metavar="KEY=VALUE",
nargs='+',
help="Set a number of key-value pairs "
"(do not put spaces before or after the = sign). "
"If a value contains spaces, you should define "
"it with double quotes: "
'foo="this is a sentence". Note that '
"values are always treated as strings.")
args = parser.parse_args()
The argument is optional and multivalued, with a minimum of one occurrence (nargs='+'
).
The result is a list of strings e.g. ["foo=hello", "bar=hello world", "baz=5"]
in args.set
, which we now need to parse (note how the shell has processed and removed the quotes!).
2. Parsing the result
For this we need 2 helper functions:
def parse_var(s):
"""
Parse a key, value pair, separated by '='
That's the reverse of ShellArgs.
On the command line (argparse) a declaration will typically look like:
foo=hello
or
foo="hello world"
"""
items = s.split('=')
key = items[0].strip() # we remove blanks around keys, as is logical
if len(items) > 1:
# rejoin the rest:
value = '='.join(items[1:])
return (key, value)
def parse_vars(items):
"""
Parse a series of key-value pairs and return a dictionary
"""
d = {}
if items:
for item in items:
key, value = parse_var(item)
d[key] = value
return d
At this point it is very simple:
# parse the key-value pairs
values = parse_vars(args.set)
You now have a dictionary:
values = {'foo':'hello', 'bar':'hello world', 'baz':'5'}
Note how the values are always returned as strings.
This method is also documented as a git gist.
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